ok, I am not understanding the logic by which the output values "A" "D" "F" are being returned

Question

print("A")
try:
    result = "test" + 5
    print("B")
except ValueError:
    print("C")
except TypeError:
    print("D")
else:
    print("E")
print("F")

boi · Accepted Answer

Hey Jason! how are you?
Alright let's check the logic, and go through each step very slowly.
First the complete code below,
python
print("A")
try:
    result = "test" + 5
    print("B")
except ValueError:
    print("C")
except TypeError:
    print("D")
else:
    print("E")
print("F")

Now breaking it down;
First step;
python
print("A")

The first step is "print("A")", pretty simple no need to overthink, so let's run it,
```python
print("A")
Output is "A". YES WE GOT "A"

Now step 2 is the try block, things can get complicated but let's focus.
python
try:
    result = "test" + 5
    print("B")

OH, this seems to be wrong because the "test" is a string type and the (5) is an int type, notice that the "test" word has the quotation marks("") at the beginning and end of it, so it makes it a string type and since the number (5) have no quotation marks and is a number, so it's an integer or int type, WE CANNOT add two different types, so this cannot be valid, and print("B") cannot execute BECAUSE the statement;
python 
result = "test" + 5

will give out a TYPE ERROR.
so print("B") is not valid, hence no output. But if we look at the next step there is an exception, meaning there is some error do this;
python 
try:
    result = "test" + 5         # This gives us a Type error because "test" is a string type and 5 is an int type
    print("B")
except ValueError:   # print("C") will execute if there is a Value Error, and in this case we have a type error not ValueError                                  
    print("C")
except TypeError:     # Now there is the error that is our type of error the TYPE ERROR, so this line of code will execute.
    print("D")
```
Since we have a type error so print("D") will execute. 
NOW, we have two outputs "A" and "D"
moving on to the next step;
python
else:
    print("E")  # This line of code will only execute IF nothing is executed in the try block and no errors were there.

Since we had a Type error, the Else line of code won't execute, So print("E") won't execute.
Now for our last step;
```python
print("F") # This code will execute directly because it has no try block, no conditions or anything.
output gives us "F"
```
print("F")  will give us "F".
So now we have all the answers
"A"     "D"     "F"
I hope you got some idea.

Jason Williams · Answer

Thanks so much, boi.  This breakdown that you provided really helped clear it up for me. I fully understand now :)

Bienvenido a la Comunidad de Treehouse

¿Buscas aprender algo nuevo?

Jason Williams

Jason Williams

No entiendo la lógica por la cual los valores de salida "A" "D" "F" se están devolviendo

2 Respuestas

tío

tío

Jason Williams

Jason Williams

tío

tío